0=2(x^2-4x-1040)

Solution for 0=2(x^2-4x-1040) equation:

0=2(x^2-4x-1040)

We move all terms to the left:

0-(2(x^2-4x-1040))=0

We add all the numbers together, and all the variables

-(2(x^2-4x-1040))=0


We calculate terms in parentheses: -(2(x^2-4x-1040)), so:

2(x^2-4x-1040)

We multiply parentheses

2x^2-8x-2080

Back to the equation:

-(2x^2-8x-2080)


We get rid of parentheses

-2x^2+8x+2080=0

a = -2; b = 8; c = +2080;
Δ = b2-4ac
Δ = 82-4·(-2)·2080
Δ = 16704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16704}=\sqrt{576*29}=\sqrt{576}*\sqrt{29}=24\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24\sqrt{29}}{2*-2}=\frac{-8-24\sqrt{29}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24\sqrt{29}}{2*-2}=\frac{-8+24\sqrt{29}}{-4}
$